SQL 行轉列並且合併顯示
/*標題：按某字段合併字符串之一(簡單合併)
作者：愛新覺羅.毓華(十八年風雨,守得冰山雪蓮花開)
時間：2008-11-06
地點：廣東深圳
描述：將如下形式的數據按id字段合併value字段。
id value
----- ------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
需要得到結果：
id value
------ -----------
1 aa,bb
2 aaa,bbb,ccc
即：group by id, 求 value 的和（字符串相加）
*/
--1、sql2000中只能用自定義的函數解決
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
create function dbo.f_str(@id int) returns varchar(100)
as
begin
declare @str varchar(1000)
set @str = ''
select @str = @str + ',' + cast(value as varchar) from tb where id = @id
set @str = right(@str , len(@str) - 1)
return @str
end
go
--調用函數
select id , value = dbo.f_str(id) from tb group by id
drop function dbo.f_str
drop table tb
--2、sql2005中的方法
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
select id, = stuff((select ',' + from tb t where id = tb.id for xml path('')) , 1 , 1 , '')
from tb
group by id
drop table tb
--3、使用游標合併數據
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
declare @t table(id int,value varchar(100))--定義結果集表變量
--定義游標並進行合併處理
declare my_cursor cursor local for
select id , value from tb
declare @id_old int , @id int , @value varchar(10) , @s varchar(100)
open my_cursor
fetch my_cursor into @id , @value
select @id_old = @id , @s=''
while @@FETCH_STATUS = 0
begin
if @id = @id_old
select @s = @s + ',' + cast(@value as varchar)
else
begin
insert @t values(@id_old , stuff(@s,1,1,''))
select @s = ',' + cast(@value as varchar) , @id_old = @id
end
fetch my_cursor into @id , @value
END
insert @t values(@id_old , stuff(@s,1,1,''))
close my_cursor
deallocate my_cursor
select * from @t
drop table tbReference: http://topic.csdn.net/u/20100511/22/919d46ac-0896-4c57-804e-01a471fc5841.html 回復 JDP 的帖子
已測試使用第二種，確定可以使用
human_id dept_no
------------ -----------
111111 aa
111111 bb
222222 aaa
222222 bbb
222222 ccc
select human_id, dept_no = stuff((select ',' + dept_no from jdptest1 where human_id = t.human_id for xml path('')) , 1 , 1 , '')
from jdptest1 as t
group by human_id
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